- #1

- 15

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A kingfisher is 30m above a lake when it accidentally drops a fish. A second kingfish 5m above the first dives toward the fish,. What's the initial speed it needs to catch the fish just before it reaches the water?

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- Thread starter LastBloomingFlower
- Start date

- #1

- 15

- 0

A kingfisher is 30m above a lake when it accidentally drops a fish. A second kingfish 5m above the first dives toward the fish,. What's the initial speed it needs to catch the fish just before it reaches the water?

- #2

- 163

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first realize that the initial velocity of the fish will be 0 since it is simply dropped so start with the projectile motion equation...

xf = xi + vit + 1/2at^2

xf = final position

xi = initial position

vi = intial velocity

t = time

a = acceleration

set the 0 level at the 2nd bird...

xf = 35m

xi = 5m

vi = 0

t = unknown

a = 9.8m/s^2

plug those into the equation to get time = 2.47s

so now we know that the 2nd bird has 2.47 seconds to catch the fish before it hits the water

use the same equation with the info for the 2nd bird.

xf = xi + vit + 1/2at^2

35 = 0 + (vi)(2.47) + (1/2)(9.8)(2.47)^2

vi = 2.08 m/s

so the 2nd bird had to start his dive going 2.08m/s to be able to catch the fish.

- #3

- 15

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Ok Thanks so much. I started out that way but I got stuck!

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